A block of mass 5 kg is pulled along a horizontal surface with a force of 20 N. If the frictional force acting on the block is 5 N, what is the acceleration of the block? (2021)
Practice Questions
1 question
Q1
A block of mass 5 kg is pulled along a horizontal surface with a force of 20 N. If the frictional force acting on the block is 5 N, what is the acceleration of the block? (2021)
2 m/s²
3 m/s²
4 m/s²
5 m/s²
Net force = Applied force - Frictional force = 20 N - 5 N = 15 N. Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².
Questions & Step-by-step Solutions
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Q
Q: A block of mass 5 kg is pulled along a horizontal surface with a force of 20 N. If the frictional force acting on the block is 5 N, what is the acceleration of the block? (2021)
Solution: Net force = Applied force - Frictional force = 20 N - 5 N = 15 N. Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².
Steps: 9
Step 1: Identify the mass of the block, which is 5 kg.
Step 2: Identify the applied force pulling the block, which is 20 N.
Step 3: Identify the frictional force acting against the block, which is 5 N.
Step 4: Calculate the net force acting on the block by subtracting the frictional force from the applied force: Net force = 20 N - 5 N.
Step 5: Perform the subtraction: 20 N - 5 N = 15 N. This is the net force.
Step 6: Use the formula F = ma to find the acceleration, where F is the net force, m is the mass, and a is the acceleration.
Step 7: Rearrange the formula to solve for acceleration: a = F/m.
Step 8: Substitute the values into the formula: a = 15 N / 5 kg.
Step 9: Perform the division: 15 N / 5 kg = 3 m/s². This is the acceleration of the block.
