What is the critical point of the function f(x) = x^2 - 4x + 4? (2022)

Practice Questions

Q1
What is the critical point of the function f(x) = x^2 - 4x + 4? (2022)
  1. 0
  2. 2
  3. 4
  4. 1

Questions & Step-by-Step Solutions

What is the critical point of the function f(x) = x^2 - 4x + 4? (2022)
  • Step 1: Start with the function f(x) = x^2 - 4x + 4.
  • Step 2: Find the derivative of the function, which is f'(x). The derivative of x^2 is 2x, and the derivative of -4x is -4. So, f'(x) = 2x - 4.
  • Step 3: Set the derivative equal to zero to find the critical points. This means we solve the equation 2x - 4 = 0.
  • Step 4: Solve the equation 2x - 4 = 0. Add 4 to both sides to get 2x = 4.
  • Step 5: Divide both sides by 2 to find x. So, x = 4 / 2 = 2.
  • Step 6: The critical point of the function is at x = 2.
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