What is the critical point of the function f(x) = x^2 - 4x + 4? (2022)

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What is the critical point of the function f(x) = x^2 - 4x + 4? (2022)
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Q: What is the critical point of the function f(x) = x^2 - 4x + 4? (2022)
Solution: Find f'(x) = 2x - 4. Set f'(x) = 0, giving 2x - 4 = 0, hence x = 2.
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