Question: If x = sin^(-1)(1/√2), then what is the value of cos(x)?
Options:
Correct Answer: √2/2
Solution:
If x = sin^(-1)(1/√2), then sin(x) = 1/√2. Therefore, cos(x) = √(1 - sin^2(x)) = √(1 - (1/√2)^2) = √(1/2) = √2/2.