If a resistor has a resistance of 8Ω and the current flowing through it is 4A, what is the power dissipated by the resistor? (2022)

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Q: If a resistor has a resistance of 8Ω and the current flowing through it is 4A, what is the power dissipated by the resistor? (2022)

Solution: Power (P) can be calculated using P = I^2 * R = (4A)^2 * 8Ω = 16 * 8 = 128W.

Steps: 7

Step 1: Identify the values given in the problem. We have a resistance (R) of 8 ohms (Ω) and a current (I) of 4 amperes (A).
Step 2: Recall the formula for power (P) in a resistor, which is P = I^2 * R.
Step 3: Substitute the current (I) into the formula. Here, I = 4A, so we calculate (4A)^2.
Step 4: Calculate (4A)^2, which is 4 * 4 = 16.
Step 5: Now, substitute this value back into the power formula: P = 16 * R, where R = 8Ω.
Step 6: Multiply 16 by 8 to find the power: 16 * 8 = 128.
Step 7: Conclude that the power dissipated by the resistor is 128 watts (W).