In a circuit with a 15V battery and two resistors of 5Ω and 10Ω in series, what

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Question: In a circuit with a 15V battery and two resistors of 5Ω and 10Ω in series, what is the voltage drop across the 10Ω resistor? (2022)

Options:

Correct Answer: 10V

Exam Year: 2022

Solution:

The total resistance is 15Ω. The current I = V/R = 15V/15Ω = 1A. Voltage drop across 10Ω = I * R = 1A * 10Ω = 10V.

In a circuit with a 15V battery and two resistors of 5Ω and 10Ω in series, what is the voltage drop across the 10Ω resistor? (2022)

In a circuit with a 15V battery and two resistors of 5Ω and 10Ω in series, what is the voltage drop across the 10Ω resistor? (2022)

Step 1: Identify the total voltage from the battery, which is 15V.
Step 2: Identify the resistors in the circuit, which are 5Ω and 10Ω.
Step 3: Calculate the total resistance in the circuit by adding the resistances together: 5Ω + 10Ω = 15Ω.
Step 4: Use Ohm's Law to find the current (I) in the circuit. The formula is I = V/R. Here, V is 15V and R is 15Ω.
Step 5: Substitute the values into the formula: I = 15V / 15Ω = 1A.
Step 6: Now, calculate the voltage drop across the 10Ω resistor using the formula: Voltage drop = I * R.
Step 7: Substitute the current (1A) and the resistance of the 10Ω resistor into the formula: Voltage drop = 1A * 10Ω.
Step 8: Calculate the voltage drop: Voltage drop = 10V.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in a circuit, expressed as V = I * R.
Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.