If two resistors of 4Ω and 12Ω are connected in series, what is the total voltag

₹0.0

Question: If two resistors of 4Ω and 12Ω are connected in series, what is the total voltage across them if the current flowing is 2A? (2020)

Options:

Correct Answer: 24V

Exam Year: 2020

Solution:

Total resistance R = 4Ω + 12Ω = 16Ω. Voltage V = I * R = 2A * 16Ω = 32V.

If two resistors of 4Ω and 12Ω are connected in series, what is the total voltage across them if the current flowing is 2A? (2020)

If two resistors of 4Ω and 12Ω are connected in series, what is the total voltage across them if the current flowing is 2A? (2020)

Step 1: Identify the resistors. We have two resistors: one is 4Ω and the other is 12Ω.
Step 2: Calculate the total resistance when resistors are in series. Add the resistances together: 4Ω + 12Ω = 16Ω.
Step 3: Identify the current flowing through the circuit. The current is given as 2A.
Step 4: Use Ohm's Law to find the total voltage. Ohm's Law states that Voltage (V) = Current (I) * Resistance (R).
Step 5: Substitute the values into the formula: V = 2A * 16Ω.
Step 6: Calculate the total voltage: 2A * 16Ω = 32V.

Ohm's Law – Ohm's Law states that the voltage across a resistor is equal to the product of the current flowing through it and the resistance (V = I * R).
Series Resistors – When resistors are connected in series, the total resistance is the sum of the individual resistances.