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What is the osmotic pressure of a solution containing 0.5 moles of solute in 1 l

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Question: What is the osmotic pressure of a solution containing 0.5 moles of solute in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol)) (2021)

Options:

  1. 12.3 atm
  2. 10.2 atm
  3. 8.2 atm
  4. 6.1 atm

Correct Answer: 10.2 atm

Exam Year: 2021

Solution: 

Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 L·atm/(K·mol) * 298 K) / 1 L = 12.3 atm.

What is the osmotic pressure of a solution containing 0.5 moles of solute in 1 l

Practice Questions

Q1
What is the osmotic pressure of a solution containing 0.5 moles of solute in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol)) (2021)
  1. 12.3 atm
  2. 10.2 atm
  3. 8.2 atm
  4. 6.1 atm

Questions & Step-by-Step Solutions

What is the osmotic pressure of a solution containing 0.5 moles of solute in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol)) (2021)
  • Step 1: Identify the formula for osmotic pressure, which is π = nRT/V.
  • Step 2: Determine the values needed for the formula: n (number of moles) = 0.5 moles, R (ideal gas constant) = 0.0821 L·atm/(K·mol), T (temperature in Kelvin) = 25 °C + 273 = 298 K, and V (volume in liters) = 1 L.
  • Step 3: Plug the values into the formula: π = (0.5 moles * 0.0821 L·atm/(K·mol) * 298 K) / 1 L.
  • Step 4: Calculate the numerator: 0.5 * 0.0821 * 298 = 12.3.
  • Step 5: Since the volume is 1 L, the osmotic pressure π = 12.3 atm.
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