What is the vapor pressure of a solution containing 2 moles of solute and 4 mole

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Question: What is the vapor pressure of a solution containing 2 moles of solute and 4 moles of solvent, assuming ideal behavior? (2022)

Options:

Correct Answer: 0.67 P0

Exam Year: 2022

Solution:

Vapor pressure = (moles of solvent / total moles) * P0 = (4 / (2 + 4)) * P0 = (4/6) * P0 = 0.67 P0.

What is the vapor pressure of a solution containing 2 moles of solute and 4 moles of solvent, assuming ideal behavior? (2022)

What is the vapor pressure of a solution containing 2 moles of solute and 4 moles of solvent, assuming ideal behavior? (2022)

Step 1: Identify the number of moles of solute and solvent. Here, we have 2 moles of solute and 4 moles of solvent.
Step 2: Calculate the total number of moles in the solution. Total moles = moles of solute + moles of solvent = 2 + 4 = 6 moles.
Step 3: Find the fraction of the solvent in the solution. This is done by dividing the moles of solvent by the total moles: 4 moles of solvent / 6 total moles = 4/6.
Step 4: Simplify the fraction. 4/6 can be simplified to 2/3 or approximately 0.67.
Step 5: Multiply the fraction of the solvent by the vapor pressure of the pure solvent (P0) to find the vapor pressure of the solution: Vapor pressure = (4/6) * P0 = 0.67 * P0.

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