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In the expansion of (3x - 4)^7, what is the coefficient of x^5? (1920)
In the expansion of (3x - 4)^7, what is the coefficient of x^5? (1920)
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In the expansion of (3x - 4)^7, what is the coefficient of x^5? (1920)
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Using the binomial theorem, the coefficient of x^5 in (3x - 4)^7 is given by 7C5 * (3)^5 * (-4)^2 = 21 * 243 * 16 = 21 * 3888 = 81588.
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Q: In the expansion of (3x - 4)^7, what is the coefficient of x^5? (1920)
Solution:
Using the binomial theorem, the coefficient of x^5 in (3x - 4)^7 is given by 7C5 * (3)^5 * (-4)^2 = 21 * 243 * 16 = 21 * 3888 = 81588.
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