In a league of 5 teams, if each team plays every other team twice, how many tota

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Question: In a league of 5 teams, if each team plays every other team twice, how many total matches are played?

Options:

Correct Answer: 20

Solution:

Each team plays 4 other teams twice, so total matches = 5 * 4 / 2 * 2 = 20.

In a league of 5 teams, if each team plays every other team twice, how many total matches are played?

In a league of 5 teams, if each team plays every other team twice, how many total matches are played?

Step 1: Identify the number of teams in the league. There are 5 teams.
Step 2: Each team plays every other team. Since there are 5 teams, each team plays against 4 other teams.
Step 3: Each match is played twice (home and away). So, for each team, the number of matches played is 4 (other teams) times 2 (for each match).
Step 4: Calculate the total matches played by all teams: 5 teams * 4 matches = 20 matches.
Step 5: Since each match is counted twice (once for each team), we divide by 2 to avoid double counting: 20 / 2 = 10 unique matches.
Step 6: Multiply the unique matches by 2 (since each match is played twice): 10 * 2 = 20 total matches.

Combinatorial Counting – Understanding how to calculate the total number of matches in a round-robin tournament format.
Double Matches – Recognizing that each match is played twice between the same teams.