In a round-robin tournament with 8 teams, each team plays every other team once.

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Question: In a round-robin tournament with 8 teams, each team plays every other team once. How many matches are played in total?

Options:

Correct Answer: 28

Solution:

In a round-robin tournament, the number of matches is given by the formula n(n-1)/2, where n is the number of teams. Here, n = 8, so the total matches = 8(8-1)/2 = 28.

In a round-robin tournament with 8 teams, each team plays every other team once.

Practice Questions

In a round-robin tournament with 8 teams, each team plays every other team once. How many matches are played in total?

Questions & Step-by-Step Solutions

In a round-robin tournament with 8 teams, each team plays every other team once. How many matches are played in total?

Step 1: Identify the number of teams in the tournament. Here, there are 8 teams.
Step 2: Understand that in a round-robin tournament, each team plays every other team exactly once.
Step 3: Use the formula for calculating the total number of matches, which is n(n-1)/2, where n is the number of teams.
Step 4: Substitute the number of teams into the formula. Here, n = 8.
Step 5: Calculate (8-1), which equals 7.
Step 6: Multiply 8 by 7 to get 56.
Step 7: Divide 56 by 2 to find the total number of matches, which equals 28.

Combinatorial Counting – Understanding how to calculate the total number of matches in a round-robin tournament using combinatorial principles.
Mathematical Formula Application – Applying the formula n(n-1)/2 to find the number of unique pairs (matches) from n teams.

In a round-robin tournament with 8 teams, each team plays every other team once.

What’s inside this PDF?

In a round-robin tournament with 8 teams, each team plays every other team once.

Practice Questions

Questions & Step-by-Step Solutions

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