For the reaction: 2A(g) + B(g) ⇌ 3C(g), if the volume of the container is decreased, what will be the effect on the equilibrium? (2022)
Practice Questions
1 question
Q1
For the reaction: 2A(g) + B(g) ⇌ 3C(g), if the volume of the container is decreased, what will be the effect on the equilibrium? (2022)
Shift to the left
Shift to the right
No change
Increase in temperature
Decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas. Here, it shifts to the right, producing more C.
Questions & Step-by-step Solutions
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Q
Q: For the reaction: 2A(g) + B(g) ⇌ 3C(g), if the volume of the container is decreased, what will be the effect on the equilibrium? (2022)
Solution: Decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas. Here, it shifts to the right, producing more C.
Steps: 8
Step 1: Understand that the reaction involves gases: 2A(g) + B(g) ⇌ 3C(g).
Step 2: Identify the number of gas moles on each side of the reaction.
Step 3: Count the moles: On the left side (reactants), there are 2 moles of A and 1 mole of B, totaling 3 moles. On the right side (products), there are 3 moles of C.
Step 4: Recognize that decreasing the volume of the container increases the pressure of the gases inside.
Step 5: Apply Le Chatelier's principle, which states that if a system at equilibrium is disturbed, it will shift to counteract the disturbance.
Step 6: Since increasing pressure favors the side with fewer moles of gas, determine which side has fewer moles.
Step 7: Compare the moles: The left side has 3 moles and the right side has 3 moles, so they are equal.
Step 8: Since both sides have the same number of moles, the equilibrium will not shift significantly in either direction.
