Find the value of the determinant \( |D| \) where \( D = \begin{pmatrix} 1 &

Practice Questions

Q1
Find the value of the determinant \( |D| \) where \( D = \begin{pmatrix} 1 & 2 & 3 \\ 0 & 1 & 4 \\ 5 & 6 & 0 \end{pmatrix} \).
  1. -12
  2. -10
  3. -8
  4. -6

Questions & Step-by-Step Solutions

Find the value of the determinant \( |D| \) where \( D = \begin{pmatrix} 1 & 2 & 3 \\ 0 & 1 & 4 \\ 5 & 6 & 0 \end{pmatrix} \).
Correct Answer: 1
  • Step 1: Write down the matrix D: D = [[1, 2, 3], [0, 1, 4], [5, 6, 0]].
  • Step 2: Identify the elements of the first row: a = 1, b = 2, c = 3.
  • Step 3: Calculate the determinant using the formula: |D| = a * det(M1) - b * det(M2) + c * det(M3), where M1, M2, M3 are the 2x2 matrices formed by removing the row and column of each element.
  • Step 4: Calculate det(M1) for element a (1): M1 = [[1, 4], [6, 0]]. The determinant is (1*0 - 4*6) = 0 - 24 = -24.
  • Step 5: Calculate det(M2) for element b (2): M2 = [[0, 4], [5, 0]]. The determinant is (0*0 - 4*5) = 0 - 20 = -20.
  • Step 6: Calculate det(M3) for element c (3): M3 = [[0, 1], [5, 6]]. The determinant is (0*6 - 1*5) = 0 - 5 = -5.
  • Step 7: Substitute the determinants back into the formula: |D| = 1*(-24) - 2*(-20) + 3*(-5).
  • Step 8: Calculate each term: 1*(-24) = -24, -2*(-20) = +40, 3*(-5) = -15.
  • Step 9: Add the results together: -24 + 40 - 15 = 1.
  • Step 10: The final value of the determinant |D| is 1.
  • Determinant Calculation – The question tests the ability to compute the determinant of a 3x3 matrix using the standard formula involving minors and cofactors.
  • Matrix Properties – Understanding the properties of determinants, such as linearity and the effect of row operations on the determinant.
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