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A force of 20 N is applied at an angle of 60° to the horizontal while moving an
A force of 20 N is applied at an angle of 60° to the horizontal while moving an object 4 m. What is the work done?
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Practice Questions
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Q1
A force of 20 N is applied at an angle of 60° to the horizontal while moving an object 4 m. What is the work done?
40 J
80 J
20 J
60 J
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Work done (W) = F × d × cos(θ) = 20 N × 4 m × cos(60°) = 20 × 4 × 0.5 = 40 J.
Questions & Step-by-step Solutions
1 item
Q
Q: A force of 20 N is applied at an angle of 60° to the horizontal while moving an object 4 m. What is the work done?
Solution:
Work done (W) = F × d × cos(θ) = 20 N × 4 m × cos(60°) = 20 × 4 × 0.5 = 40 J.
Steps: 9
Show Steps
Step 1: Identify the force applied, which is 20 N.
Step 2: Identify the distance moved by the object, which is 4 m.
Step 3: Identify the angle of the force with respect to the horizontal, which is 60°.
Step 4: Use the formula for work done: W = F × d × cos(θ).
Step 5: Substitute the values into the formula: W = 20 N × 4 m × cos(60°).
Step 6: Calculate cos(60°), which is 0.5.
Step 7: Substitute cos(60°) into the equation: W = 20 N × 4 m × 0.5.
Step 8: Perform the multiplication: 20 × 4 = 80, then 80 × 0.5 = 40.
Step 9: Conclude that the work done is 40 J.
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