In a series circuit with a 12 V battery and two resistors of 4 Ω and 8 Ω, what i

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Question: In a series circuit with a 12 V battery and two resistors of 4 Ω and 8 Ω, what is the current flowing through the circuit?

Options:

Correct Answer: 1 A

Solution:

Total resistance R_total = R1 + R2 = 4 Ω + 8 Ω = 12 Ω. Using Ohm\'s Law, I = V/R = 12 V / 12 Ω = 1 A.

In a series circuit with a 12 V battery and two resistors of 4 Ω and 8 Ω, what is the current flowing through the circuit?

In a series circuit with a 12 V battery and two resistors of 4 Ω and 8 Ω, what is the current flowing through the circuit?

Step 1: Identify the voltage of the battery, which is 12 V.
Step 2: Identify the resistors in the circuit, which are 4 Ω and 8 Ω.
Step 3: Calculate the total resistance in the circuit by adding the resistances together: R_total = R1 + R2 = 4 Ω + 8 Ω.
Step 4: Perform the addition: R_total = 4 Ω + 8 Ω = 12 Ω.
Step 5: Use Ohm's Law to find the current: I = V / R_total.
Step 6: Substitute the values into the formula: I = 12 V / 12 Ω.
Step 7: Perform the division: I = 1 A.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as I = V/R.
Series Circuit – A circuit configuration where components are connected end-to-end, resulting in the same current flowing through each component.
Total Resistance in Series – In a series circuit, the total resistance is the sum of the individual resistances.