What is the resistance of a wire of length 2 m and cross-sectional area 1 mm² if

₹0.0

Question: What is the resistance of a wire of length 2 m and cross-sectional area 1 mm² if the resistivity of the material is 1.7 x 10^-8 Ωm?

Options:

Correct Answer: 0.034 Ω

Solution:

Resistance R = ρ * (L/A). Here, R = (1.7 x 10^-8 Ωm) * (2 m / (1 x 10^-6 m²)) = 0.034 Ω.

What is the resistance of a wire of length 2 m and cross-sectional area 1 mm² if the resistivity of the material is 1.7 x 10^-8 Ωm?

What is the resistance of a wire of length 2 m and cross-sectional area 1 mm² if the resistivity of the material is 1.7 x 10^-8 Ωm?

Step 1: Identify the formula for resistance, which is R = ρ * (L/A).
Step 2: Write down the values given in the question: resistivity (ρ) = 1.7 x 10^-8 Ωm, length (L) = 2 m, and cross-sectional area (A) = 1 mm².
Step 3: Convert the cross-sectional area from mm² to m². Since 1 mm² = 1 x 10^-6 m², we have A = 1 x 10^-6 m².
Step 4: Substitute the values into the formula: R = (1.7 x 10^-8 Ωm) * (2 m / (1 x 10^-6 m²)).
Step 5: Calculate the value inside the parentheses: 2 m / (1 x 10^-6 m²) = 2 x 10^6 m⁻¹.
Step 6: Now multiply: R = (1.7 x 10^-8 Ωm) * (2 x 10^6 m⁻¹).
Step 7: Perform the multiplication: R = 3.4 x 10^-2 Ω, which is equal to 0.034 Ω.

No concepts available.