What is the magnetic field strength at the center of a circular loop of radius 0

Practice Questions

Q1
What is the magnetic field strength at the center of a circular loop of radius 0.1 m carrying a current of 5 A?
  1. 0.1 T
  2. 0.2 T
  3. 0.5 T
  4. 1 T

Questions & Step-by-Step Solutions

What is the magnetic field strength at the center of a circular loop of radius 0.1 m carrying a current of 5 A?
  • Step 1: Identify the formula for the magnetic field at the center of a circular loop, which is B = (μ₀ * I) / (2 * R).
  • Step 2: Note the values needed for the calculation: μ₀ (the permeability of free space) is 4π x 10^-7 Tm/A, I (the current) is 5 A, and R (the radius) is 0.1 m.
  • Step 3: Substitute the values into the formula: B = (4π x 10^-7 * 5) / (2 * 0.1).
  • Step 4: Calculate the denominator: 2 * 0.1 = 0.2.
  • Step 5: Calculate the numerator: 4π x 10^-7 * 5 = 20π x 10^-7.
  • Step 6: Now divide the numerator by the denominator: B = (20π x 10^-7) / 0.2.
  • Step 7: Simplify the division: B = 100π x 10^-7 T.
  • Step 8: Calculate the numerical value: B ≈ 0.1 T (using π ≈ 3.14).
No concepts available.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely