A ball is thrown upwards with a speed of 25 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

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Q: A ball is thrown upwards with a speed of 25 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

Solution: Time to reach maximum height = initial velocity / g = 25 / 10 = 2.5 s.

Steps: 7

Step 1: Understand that when a ball is thrown upwards, it will eventually stop rising and start falling back down. The point where it stops rising is called the maximum height.
Step 2: Know that the initial speed of the ball is 25 m/s. This is how fast the ball is going when it is thrown upwards.
Step 3: Recognize that gravity (g) pulls the ball downwards at a rate of 10 m/s². This means that for every second the ball goes up, it slows down by 10 m/s.
Step 4: To find out how long it takes to reach the maximum height, we can use the formula: Time to reach maximum height = initial velocity / g.
Step 5: Plug in the values: initial velocity = 25 m/s and g = 10 m/s². So, Time = 25 / 10.
Step 6: Calculate the time: 25 divided by 10 equals 2.5 seconds.
Step 7: Conclude that it will take 2.5 seconds for the ball to reach its maximum height.