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A ball is dropped from a height of 45 m. How long will it take to reach the grou
A ball is dropped from a height of 45 m. How long will it take to reach the ground? (g = 10 m/s²) (2023)
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Q1
A ball is dropped from a height of 45 m. How long will it take to reach the ground? (g = 10 m/s²) (2023)
3 s
4 s
5 s
6 s
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Time = √(2h/g) = √(2 × 45 m/10 m/s²) = √(9) = 3 s
Questions & Step-by-step Solutions
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Q
Q: A ball is dropped from a height of 45 m. How long will it take to reach the ground? (g = 10 m/s²) (2023)
Solution:
Time = √(2h/g) = √(2 × 45 m/10 m/s²) = √(9) = 3 s
Steps: 7
Show Steps
Step 1: Identify the height from which the ball is dropped. In this case, the height (h) is 45 meters.
Step 2: Identify the acceleration due to gravity (g). Here, g is given as 10 m/s².
Step 3: Use the formula to calculate the time (t) it takes for the ball to reach the ground: t = √(2h/g).
Step 4: Substitute the values into the formula: t = √(2 × 45 m / 10 m/s²).
Step 5: Calculate the value inside the square root: 2 × 45 m = 90 m, and then 90 m / 10 m/s² = 9.
Step 6: Now, take the square root of 9: √(9) = 3.
Step 7: Therefore, the time it takes for the ball to reach the ground is 3 seconds.
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