If an object is thrown upwards with a speed of 20 m/s, how high will it go befor

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Question: If an object is thrown upwards with a speed of 20 m/s, how high will it go before coming to rest? (g = 10 m/s²) (2023)

Options:

Correct Answer: 40 m

Exam Year: 2023

Solution:

Height = (Initial Speed)²/(2 × g) = (20 m/s)²/(2 × 10 m/s²) = 20 m

If an object is thrown upwards with a speed of 20 m/s, how high will it go before coming to rest? (g = 10 m/s²) (2023)

If an object is thrown upwards with a speed of 20 m/s, how high will it go before coming to rest? (g = 10 m/s²) (2023)

Step 1: Identify the initial speed of the object. In this case, it is 20 m/s.
Step 2: Identify the acceleration due to gravity (g). Here, it is given as 10 m/s².
Step 3: Use the formula to calculate the maximum height: Height = (Initial Speed)² / (2 × g).
Step 4: Substitute the values into the formula: Height = (20 m/s)² / (2 × 10 m/s²).
Step 5: Calculate (20 m/s)², which equals 400 m²/s².
Step 6: Calculate 2 × 10 m/s², which equals 20 m/s².
Step 7: Divide 400 m²/s² by 20 m/s² to find the height: 400 m²/s² / 20 m/s² = 20 m.
Step 8: Conclude that the maximum height the object will reach is 20 meters.

Kinematics – The question tests the understanding of the kinematic equations of motion, specifically the calculation of maximum height in projectile motion.
Energy Conservation – It also touches on the concept of energy conservation, where kinetic energy is converted to potential energy at the peak of the motion.