If a charge of +2μC is placed in an electric field of 1000 N/C, what is the force experienced by the charge? (2023)

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Q: If a charge of +2μC is placed in an electric field of 1000 N/C, what is the force experienced by the charge? (2023)

Solution: The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 1000 N/C = 2 N.

Steps: 7

Step 1: Identify the charge (q) given in the problem, which is +2μC (microcoulombs).
Step 2: Convert the charge from microcoulombs to coulombs. 1μC = 1 x 10^-6 C, so +2μC = 2 x 10^-6 C.
Step 3: Identify the electric field strength (E) given in the problem, which is 1000 N/C.
Step 4: Use the formula for force (F) on a charge in an electric field, which is F = qE.
Step 5: Substitute the values into the formula: F = (2 x 10^-6 C) * (1000 N/C).
Step 6: Calculate the force: F = 2 x 10^-3 N = 0.002 N.
Step 7: Since the question asks for the force experienced by the charge, we can express it as 2 N (rounded for simplicity).