If z = re^(iθ), what is the value of r if z = 4 + 3i?

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Q: If z = re^(iθ), what is the value of r if z = 4 + 3i?

Solution: r = |z| = √(4^2 + 3^2) = √(16 + 9) = √25 = 5.

Steps: 9

Step 1: Identify the complex number z, which is given as z = 4 + 3i.
Step 2: Recall that in the expression z = re^(iθ), r represents the magnitude (or absolute value) of the complex number z.
Step 3: To find the magnitude r, use the formula r = |z| = √(a^2 + b^2), where a is the real part and b is the imaginary part of z.
Step 4: In our case, the real part a = 4 and the imaginary part b = 3.
Step 5: Substitute the values into the formula: r = √(4^2 + 3^2).
Step 6: Calculate 4^2, which is 16, and 3^2, which is 9.
Step 7: Add the results: 16 + 9 = 25.
Step 8: Take the square root of 25: √25 = 5.
Step 9: Therefore, the value of r is 5.