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If the equation 2x^2 + 3x + k = 0 has one root equal to 1, what is the value of
If the equation 2x^2 + 3x + k = 0 has one root equal to 1, what is the value of k?
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Q1
If the equation 2x^2 + 3x + k = 0 has one root equal to 1, what is the value of k?
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Substituting x = 1 gives 2(1)^2 + 3(1) + k = 0 => 2 + 3 + k = 0 => k = -5.
Questions & Step-by-step Solutions
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Q
Q: If the equation 2x^2 + 3x + k = 0 has one root equal to 1, what is the value of k?
Solution:
Substituting x = 1 gives 2(1)^2 + 3(1) + k = 0 => 2 + 3 + k = 0 => k = -5.
Steps: 7
Show Steps
Step 1: Start with the equation 2x^2 + 3x + k = 0.
Step 2: We know one root of the equation is x = 1.
Step 3: Substitute x = 1 into the equation: 2(1)^2 + 3(1) + k = 0.
Step 4: Calculate (1)^2, which is 1, so we have 2(1) + 3(1) + k = 0.
Step 5: This simplifies to 2 + 3 + k = 0.
Step 6: Add 2 and 3 together to get 5, so we have 5 + k = 0.
Step 7: To find k, subtract 5 from both sides: k = -5.
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