If a quadratic equation has roots 2 and -3, what is the equation in standard for

Practice Questions

Q1
If a quadratic equation has roots 2 and -3, what is the equation in standard form?
  1. x^2 + x - 6 = 0
  2. x^2 - x - 6 = 0
  3. x^2 - x + 6 = 0
  4. x^2 + 5x - 6 = 0

Questions & Step-by-Step Solutions

If a quadratic equation has roots 2 and -3, what is the equation in standard form?
Correct Answer: x^2 + x - 6 = 0
  • Step 1: Identify the roots of the quadratic equation. The roots given are 2 and -3.
  • Step 2: Write the factors of the equation using the roots. For root 2, the factor is (x - 2). For root -3, the factor is (x + 3).
  • Step 3: Combine the factors into one equation: (x - 2)(x + 3) = 0.
  • Step 4: Expand the equation by multiplying the factors: (x - 2)(x + 3) = x^2 + 3x - 2x - 6.
  • Step 5: Simplify the equation: x^2 + 3x - 2x - 6 = x^2 + x - 6.
  • Step 6: Write the final equation in standard form: x^2 + x - 6 = 0.
  • Quadratic Equations – Understanding how to form a quadratic equation from its roots.
  • Factoring – Using the roots to create factors and then expanding them to standard form.
  • Standard Form of a Quadratic – Recognizing the standard form of a quadratic equation as ax^2 + bx + c = 0.
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