In a reaction, 2 moles of hydrogen gas react with 1 mole of oxygen gas to form water. How many grams of water are produced? (2020)

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Q: In a reaction, 2 moles of hydrogen gas react with 1 mole of oxygen gas to form water. How many grams of water are produced? (2020)

Solution: 2H2 + O2 → 2H2O. 1 mole of water weighs 18 g, so 2 moles produce 36 g. Thus, 18 g of water is produced from 1 mole of O2.

Steps: 5

Step 1: Write down the chemical reaction: 2H2 + O2 → 2H2O.
Step 2: Identify how many moles of water are produced. From the reaction, 2 moles of H2 and 1 mole of O2 produce 2 moles of H2O.
Step 3: Find out how much 1 mole of water weighs. 1 mole of water (H2O) weighs 18 grams.
Step 4: Calculate the total weight of water produced. Since 2 moles of water are produced, multiply 2 moles by 18 grams: 2 moles × 18 g/mole = 36 grams.
Step 5: Determine how much water is produced from 1 mole of O2. Since 1 mole of O2 produces 2 moles of H2O, it produces 36 grams of water.