In the expansion of (2x - 3)^5, what is the coefficient of x^3?

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Q: In the expansion of (2x - 3)^5, what is the coefficient of x^3?

Solution: The coefficient of x^3 is C(5,3) * (2)^3 * (-3)^2 = 10 * 8 * 9 = -720.

Steps: 11

Step 1: Identify the expression to expand, which is (2x - 3)^5.
Step 2: Recognize that we need to find the coefficient of x^3 in the expansion.
Step 3: Use the Binomial Theorem, which states that (a + b)^n = Σ [C(n, k) * a^(n-k) * b^k] for k = 0 to n.
Step 4: In our case, a = 2x, b = -3, and n = 5.
Step 5: We want the term where the power of x is 3, which means we need to find the term where k = 2 (since 5 - k = 3).
Step 6: Calculate C(5, 2), which is the number of ways to choose 2 from 5. C(5, 2) = 5! / (2!(5-2)!) = 10.
Step 7: Calculate (2x)^(5-2) = (2x)^3 = 2^3 * x^3 = 8x^3.
Step 8: Calculate (-3)^2 = 9.
Step 9: Multiply the results: Coefficient = C(5, 2) * (2^3) * (-3)^2 = 10 * 8 * 9.
Step 10: Calculate 10 * 8 = 80, then 80 * 9 = 720.
Step 11: Since we are multiplying by (-3)^2, the coefficient of x^3 is positive 720.