A bag contains 5 red, 3 blue, and 2 green balls. If one ball is drawn at random,

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Question: A bag contains 5 red, 3 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is not blue?

Options:

Correct Answer: 0.7

Solution:

The total number of balls is 10. The number of non-blue balls is 7 (5 red + 2 green). Thus, the probability is 7/10 = 0.7.

A bag contains 5 red, 3 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is not blue?

A bag contains 5 red, 3 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is not blue?

Step 1: Count the total number of balls in the bag. There are 5 red, 3 blue, and 2 green balls.
Step 2: Add the number of red, blue, and green balls together: 5 + 3 + 2 = 10. So, the total number of balls is 10.
Step 3: Count the number of non-blue balls. Non-blue balls are red and green. There are 5 red and 2 green.
Step 4: Add the number of red and green balls together: 5 + 2 = 7. So, there are 7 non-blue balls.
Step 5: To find the probability of drawing a non-blue ball, divide the number of non-blue balls by the total number of balls: 7 (non-blue) / 10 (total) = 0.7.
Step 6: The probability that the ball drawn is not blue is 0.7.

Probability – The likelihood of an event occurring, calculated as the ratio of favorable outcomes to the total number of possible outcomes.
Counting Outcomes – Understanding how to count the total number of items and categorize them based on specific criteria (in this case, color).