A bag contains 5 red, 3 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is not blue?
Practice Questions
1 question
Q1
A bag contains 5 red, 3 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is not blue?
0.5
0.6
0.7
0.8
The total number of balls is 10. The number of non-blue balls is 7 (5 red + 2 green). Thus, the probability is 7/10 = 0.7.
Questions & Step-by-step Solutions
1 item
Q
Q: A bag contains 5 red, 3 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is not blue?
Solution: The total number of balls is 10. The number of non-blue balls is 7 (5 red + 2 green). Thus, the probability is 7/10 = 0.7.
Steps: 6
Step 1: Count the total number of balls in the bag. There are 5 red, 3 blue, and 2 green balls.
Step 2: Add the number of red, blue, and green balls together: 5 + 3 + 2 = 10. So, the total number of balls is 10.
Step 3: Count the number of non-blue balls. Non-blue balls are red and green. There are 5 red and 2 green.
Step 4: Add the number of red and green balls together: 5 + 2 = 7. So, there are 7 non-blue balls.
Step 5: To find the probability of drawing a non-blue ball, divide the number of non-blue balls by the total number of balls: 7 (non-blue) / 10 (total) = 0.7.
Step 6: The probability that the ball drawn is not blue is 0.7.
