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A ball is thrown upwards with an initial velocity of 20 m/s. How long will it ta
A ball is thrown upwards with an initial velocity of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)
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A ball is thrown upwards with an initial velocity of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)
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Using the formula: t = v/g = 20/10 = 2 s.
Questions & Step-by-step Solutions
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Q
Q: A ball is thrown upwards with an initial velocity of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)
Solution:
Using the formula: t = v/g = 20/10 = 2 s.
Steps: 6
Show Steps
Step 1: Understand that when a ball is thrown upwards, it will eventually stop rising and reach its maximum height before falling back down.
Step 2: Know that the initial velocity (v) of the ball is 20 m/s.
Step 3: Recognize that the acceleration due to gravity (g) is 10 m/s², which acts downwards.
Step 4: Use the formula to find the time (t) it takes to reach maximum height: t = v / g.
Step 5: Substitute the values into the formula: t = 20 m/s / 10 m/s².
Step 6: Calculate the time: t = 2 seconds.
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