A mixture contains 60% of liquid X and 40% of liquid Y. If 10 liters of liquid Y is added, what will be the new percentage of liquid X in the mixture if the total volume becomes 30 liters?
Practice Questions
1 question
Q1
A mixture contains 60% of liquid X and 40% of liquid Y. If 10 liters of liquid Y is added, what will be the new percentage of liquid X in the mixture if the total volume becomes 30 liters?
50%
40%
60%
70%
Initial volume of Y = 40% of 20 liters = 8 liters. New volume of Y = 8 + 10 = 18 liters. Volume of X = 30 - 18 = 12 liters. Percentage of X = (12/30) * 100 = 40%.
Questions & Step-by-step Solutions
1 item
Q
Q: A mixture contains 60% of liquid X and 40% of liquid Y. If 10 liters of liquid Y is added, what will be the new percentage of liquid X in the mixture if the total volume becomes 30 liters?
Solution: Initial volume of Y = 40% of 20 liters = 8 liters. New volume of Y = 8 + 10 = 18 liters. Volume of X = 30 - 18 = 12 liters. Percentage of X = (12/30) * 100 = 40%.
Steps: 9
Step 1: Understand that the mixture has 60% liquid X and 40% liquid Y.
Step 2: Calculate the initial total volume of the mixture. Since we are not given it directly, we can assume it is 20 liters (because 60% + 40% = 100%).
Step 3: Calculate the initial volume of liquid Y. Since it is 40% of 20 liters, the volume of Y is 0.4 * 20 = 8 liters.
Step 4: Add 10 liters of liquid Y to the initial volume of Y. So, new volume of Y = 8 liters + 10 liters = 18 liters.
Step 5: Calculate the new total volume of the mixture. It is given that the total volume becomes 30 liters.
Step 6: Calculate the volume of liquid X in the new mixture. Since the total volume is 30 liters and the volume of Y is 18 liters, the volume of X = 30 liters - 18 liters = 12 liters.
Step 7: Calculate the new percentage of liquid X in the mixture. Use the formula: (Volume of X / Total Volume) * 100 = (12 liters / 30 liters) * 100.
