A circuit consists of a 9V battery and two resistors of 3Ω and 6Ω in series. What is the current flowing through the circuit? (2021)
Practice Questions
1 question
Q1
A circuit consists of a 9V battery and two resistors of 3Ω and 6Ω in series. What is the current flowing through the circuit? (2021)
1A
2A
3A
4A
Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V / 9Ω = 1A.
Questions & Step-by-step Solutions
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Q
Q: A circuit consists of a 9V battery and two resistors of 3Ω and 6Ω in series. What is the current flowing through the circuit? (2021)
Solution: Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V / 9Ω = 1A.
Steps: 5
Step 1: Identify the components in the circuit. We have a 9V battery and two resistors: one with a resistance of 3Ω and another with a resistance of 6Ω.
Step 2: Calculate the total resistance in the circuit. Since the resistors are in series, we add their resistances together: 3Ω + 6Ω = 9Ω.
Step 3: Use Ohm's Law to find the current. Ohm's Law states that current (I) is equal to voltage (V) divided by resistance (R). Here, V = 9V and R = 9Ω.
Step 4: Substitute the values into the formula: I = 9V / 9Ω.
