Question: A rectangle has a length that is twice its width. If the perimeter of the rectangle is 48 cm, what is the width?
Options:
Correct Answer: 12 cm
Solution:
Let the width be w. Then the length is 2w. The perimeter P = 2(length + width) = 2(2w + w) = 6w. Setting this equal to 48 gives 6w = 48, so w = 8 cm.