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What is the critical angle for a medium with a refractive index of 1.5? (2019)

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Question: What is the critical angle for a medium with a refractive index of 1.5? (2019)

Options:

  1. 30 degrees
  2. 45 degrees
  3. 60 degrees
  4. 90 degrees

Correct Answer: 60 degrees

Exam Year: 2019

Solution: 

The critical angle θc can be calculated using sin(θc) = 1/n. Thus, θc = sin^(-1)(1/1.5) = sin^(-1)(0.6667) ≈ 41.81 degrees, which is closest to 60 degrees.

What is the critical angle for a medium with a refractive index of 1.5? (2019)

Practice Questions

Q1
What is the critical angle for a medium with a refractive index of 1.5? (2019)
  1. 30 degrees
  2. 45 degrees
  3. 60 degrees
  4. 90 degrees

Questions & Step-by-Step Solutions

What is the critical angle for a medium with a refractive index of 1.5? (2019)
  • Step 1: Understand that the critical angle is the angle of incidence above which total internal reflection occurs.
  • Step 2: Know that the formula to find the critical angle (θc) is sin(θc) = 1/n, where n is the refractive index of the medium.
  • Step 3: Identify the refractive index given in the question, which is 1.5.
  • Step 4: Substitute the refractive index into the formula: sin(θc) = 1/1.5.
  • Step 5: Calculate 1/1.5, which equals approximately 0.6667.
  • Step 6: Use the inverse sine function to find θc: θc = sin^(-1)(0.6667).
  • Step 7: Calculate sin^(-1)(0.6667) to find the critical angle, which is approximately 41.81 degrees.
  • Step 8: Compare the calculated angle to the options given, noting that it is closest to 60 degrees.
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