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A 10 kg object is dropped from a height of 20 m. What is its potential energy at
A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 10 m/s²) (2022)
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A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 10 m/s²) (2022)
200 J
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Potential Energy (PE) = m * g * h = 10 kg * 10 m/s² * 20 m = 2000 J
Questions & Step-by-step Solutions
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Q: A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 10 m/s²) (2022)
Solution:
Potential Energy (PE) = m * g * h = 10 kg * 10 m/s² * 20 m = 2000 J
Steps: 6
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 10 kg.
Step 2: Identify the height from which the object is dropped. The height (h) is 20 m.
Step 3: Identify the acceleration due to gravity. Here, g is given as 10 m/s².
Step 4: Use the formula for potential energy (PE), which is PE = m * g * h.
Step 5: Substitute the values into the formula: PE = 10 kg * 10 m/s² * 20 m.
Step 6: Calculate the potential energy: 10 * 10 * 20 = 2000 J.
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