Determine the critical points of f(x) = 3x^4 - 8x^3 + 6. (2021)

Practice Questions

Q1
Determine the critical points of f(x) = 3x^4 - 8x^3 + 6. (2021)
  1. (0, 6)
  2. (1, 1)
  3. (2, 0)
  4. (3, -1)

Questions & Step-by-Step Solutions

Determine the critical points of f(x) = 3x^4 - 8x^3 + 6. (2021)
  • Step 1: Write down the function f(x) = 3x^4 - 8x^3 + 6.
  • Step 2: Find the derivative of the function, f'(x). The derivative tells us the slope of the function.
  • Step 3: Calculate the derivative: f'(x) = 12x^3 - 24x^2.
  • Step 4: Set the derivative equal to zero to find critical points: 12x^3 - 24x^2 = 0.
  • Step 5: Factor the equation: 12x^2(x - 2) = 0.
  • Step 6: Solve for x by setting each factor to zero: 12x^2 = 0 gives x = 0, and x - 2 = 0 gives x = 2.
  • Step 7: The critical points are x = 0 and x = 2.
  • Step 8: To check the behavior of the function at these points, you can evaluate f(1) to see the value of the function at x = 1.
  • Critical Points – Critical points are found by setting the derivative of a function to zero and solving for x.
  • Derivative Calculation – Finding the first derivative of a polynomial function to analyze its behavior.
  • Function Evaluation – Evaluating the original function at specific points to determine their nature (maxima, minima, or saddle points).
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