A jar contains 5 red, 3 blue, and 2 yellow marbles. If one marble is drawn, what

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Question: A jar contains 5 red, 3 blue, and 2 yellow marbles. If one marble is drawn, what is the probability that it is either red or yellow?

Options:

Correct Answer: 7/10

Solution:

Total marbles = 5 + 3 + 2 = 10. Probability of red or yellow = (Number of red + Number of yellow) / Total = (5 + 2) / 10 = 7/10.

A jar contains 5 red, 3 blue, and 2 yellow marbles. If one marble is drawn, what is the probability that it is either red or yellow?

A jar contains 5 red, 3 blue, and 2 yellow marbles. If one marble is drawn, what is the probability that it is either red or yellow?

Step 1: Count the number of red marbles. There are 5 red marbles.
Step 2: Count the number of blue marbles. There are 3 blue marbles.
Step 3: Count the number of yellow marbles. There are 2 yellow marbles.
Step 4: Add the total number of marbles together. 5 red + 3 blue + 2 yellow = 10 total marbles.
Step 5: Count the number of marbles that are either red or yellow. There are 5 red + 2 yellow = 7 marbles.
Step 6: Calculate the probability of drawing a red or yellow marble. This is done by dividing the number of red or yellow marbles by the total number of marbles: 7 / 10.
Step 7: The final probability of drawing either a red or yellow marble is 7/10.

Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
Counting Outcomes – Understanding how to count the total number of outcomes and favorable outcomes in a probability scenario.