A bag contains 4 white balls and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?
Practice Questions
1 question
Q1
A bag contains 4 white balls and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?
2/5
3/5
4/5
1/5
Total balls = 4 + 6 = 10. Probability of not drawing a black ball = Number of white balls / Total balls = 4/10 = 2/5.
Questions & Step-by-step Solutions
1 item
Q
Q: A bag contains 4 white balls and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?
Solution: Total balls = 4 + 6 = 10. Probability of not drawing a black ball = Number of white balls / Total balls = 4/10 = 2/5.
Steps: 5
Step 1: Count the total number of balls in the bag. There are 4 white balls and 6 black balls.
Step 2: Add the number of white balls and black balls together. So, 4 + 6 = 10 total balls.
Step 3: Identify how many balls are not black. Since there are only white balls that are not black, there are 4 white balls.
Step 4: To find the probability of drawing a ball that is not black, divide the number of white balls by the total number of balls. This is 4 (white balls) divided by 10 (total balls).
Step 5: Simplify the fraction 4/10. This can be simplified to 2/5.
