A bag contains 4 white balls and 6 black balls. If one ball is drawn at random,

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Question: A bag contains 4 white balls and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?

Options:

Correct Answer: 4/5

Solution:

Total balls = 4 + 6 = 10. Probability of not drawing a black ball = Number of white balls / Total balls = 4/10 = 2/5.

A bag contains 4 white balls and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?

A bag contains 4 white balls and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?

Step 1: Count the total number of balls in the bag. There are 4 white balls and 6 black balls.
Step 2: Add the number of white balls and black balls together. So, 4 + 6 = 10 total balls.
Step 3: Identify how many balls are not black. Since there are only white balls that are not black, there are 4 white balls.
Step 4: To find the probability of drawing a ball that is not black, divide the number of white balls by the total number of balls. This is 4 (white balls) divided by 10 (total balls).
Step 5: Simplify the fraction 4/10. This can be simplified to 2/5.

Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
Complementary Events – Understanding that the probability of an event not occurring can be calculated by considering the total outcomes minus the favorable outcomes.