A box contains 3 red, 5 blue, and 2 green balls. If one ball is drawn at random,

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Question: A box contains 3 red, 5 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is blue?

Options:

Correct Answer: 1/5

Solution:

Total balls = 3 + 5 + 2 = 10. Probability of drawing a blue ball = Number of blue balls / Total balls = 5/10 = 1/2.

A box contains 3 red, 5 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is blue?

A box contains 3 red, 5 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is blue?

Step 1: Count the number of red balls. There are 3 red balls.
Step 2: Count the number of blue balls. There are 5 blue balls.
Step 3: Count the number of green balls. There are 2 green balls.
Step 4: Add the number of all balls together: 3 red + 5 blue + 2 green = 10 total balls.
Step 5: Identify how many of the balls are blue. There are 5 blue balls.
Step 6: Calculate the probability of drawing a blue ball by dividing the number of blue balls by the total number of balls: 5 blue balls / 10 total balls.
Step 7: Simplify the fraction: 5/10 = 1/2.

Probability – The likelihood of an event occurring, calculated as the ratio of favorable outcomes to the total number of possible outcomes.
Counting Principles – Understanding how to count the total number of items in a set to determine probabilities.