A box contains 3 red, 5 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is blue?
Practice Questions
1 question
Q1
A box contains 3 red, 5 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is blue?
1/10
1/5
1/2
1/3
Total balls = 3 + 5 + 2 = 10. Probability of drawing a blue ball = Number of blue balls / Total balls = 5/10 = 1/2.
Questions & Step-by-step Solutions
1 item
Q
Q: A box contains 3 red, 5 blue, and 2 green balls. If one ball is drawn at random, what is the probability that it is blue?
Solution: Total balls = 3 + 5 + 2 = 10. Probability of drawing a blue ball = Number of blue balls / Total balls = 5/10 = 1/2.
Steps: 7
Step 1: Count the number of red balls. There are 3 red balls.
Step 2: Count the number of blue balls. There are 5 blue balls.
Step 3: Count the number of green balls. There are 2 green balls.
Step 4: Add the number of all balls together: 3 red + 5 blue + 2 green = 10 total balls.
Step 5: Identify how many of the balls are blue. There are 5 blue balls.
Step 6: Calculate the probability of drawing a blue ball by dividing the number of blue balls by the total number of balls: 5 blue balls / 10 total balls.
