A capacitor is charged to a potential difference of 12V. If the charge on the ca

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Question: A capacitor is charged to a potential difference of 12V. If the charge on the capacitor is 24μC, what is its capacitance? (2019)

Options:

Correct Answer: 4μF

Exam Year: 2019

Solution:

Capacitance C is given by C = Q/V. Here, C = 24μC / 12V = 2μF.

A capacitor is charged to a potential difference of 12V. If the charge on the capacitor is 24μC, what is its capacitance? (2019)

A capacitor is charged to a potential difference of 12V. If the charge on the capacitor is 24μC, what is its capacitance? (2019)

Step 1: Understand the formula for capacitance, which is C = Q/V, where C is capacitance, Q is charge, and V is voltage.
Step 2: Identify the values given in the question: Q (charge) is 24μC and V (voltage) is 12V.
Step 3: Convert the charge from microcoulombs to coulombs if necessary. 24μC is equal to 24 x 10^-6 C.
Step 4: Plug the values into the formula: C = 24μC / 12V.
Step 5: Calculate the capacitance: C = 24μC / 12V = 2μF.
Step 6: State the final answer: The capacitance of the capacitor is 2μF.

Capacitance – Capacitance is the ability of a capacitor to store charge per unit voltage, calculated using the formula C = Q/V.