What is the electric field due to a point charge of +5 µC at a distance of 0.2 m
Practice Questions
Q1
What is the electric field due to a point charge of +5 µC at a distance of 0.2 m? (2022)
11250 N/C
5625 N/C
22500 N/C
4500 N/C
Questions & Step-by-Step Solutions
What is the electric field due to a point charge of +5 µC at a distance of 0.2 m? (2022)
Step 1: Identify the formula for electric field due to a point charge, which is E = k * |q| / r².
Step 2: Determine the values needed for the formula: k (Coulomb's constant) = 9 × 10^9 N m²/C², q (the charge) = +5 µC = 5 × 10^-6 C, and r (the distance) = 0.2 m.
Step 3: Substitute the values into the formula: E = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.2 m)².
Step 4: Calculate (0.2 m)², which is 0.04 m².
Step 5: Now calculate E = (9 × 10^9) * (5 × 10^-6) / 0.04.
Step 6: Multiply 9 × 10^9 by 5 × 10^-6 to get 45,000 N m²/C.
Step 7: Divide 45,000 N m²/C by 0.04 m² to get 1,125,000 N/C.
Step 8: Write the final answer in scientific notation: 1,125,000 N/C = 11250 N/C.
