In a series circuit with a 9V battery and three resistors of 1Ω, 2Ω, and 3Ω, what is the total resistance? (2019)

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In a series circuit with a 9V battery and three resistors of 1Ω, 2Ω, and 3Ω, what is the total resistance? (2019)

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Q: In a series circuit with a 9V battery and three resistors of 1Ω, 2Ω, and 3Ω, what is the total resistance? (2019)
Solution: Total resistance in series is R_total = R1 + R2 + R3 = 1 + 2 + 3 = 6Ω.
Steps: 0

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