In a series circuit with a 9V battery and three resistors of 1Ω, 2Ω, and 3Ω, wha

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Question: In a series circuit with a 9V battery and three resistors of 1Ω, 2Ω, and 3Ω, what is the total resistance? (2019)

Options:

Correct Answer: 6Ω

Exam Year: 2019

Solution:

Total resistance in series is R_total = R1 + R2 + R3 = 1 + 2 + 3 = 6Ω.

In a series circuit with a 9V battery and three resistors of 1Ω, 2Ω, and 3Ω, what is the total resistance? (2019)

In a series circuit with a 9V battery and three resistors of 1Ω, 2Ω, and 3Ω, what is the total resistance? (2019)

Step 1: Identify the resistors in the circuit. We have three resistors: R1 = 1Ω, R2 = 2Ω, and R3 = 3Ω.
Step 2: Understand that in a series circuit, the total resistance is found by adding all the resistances together.
Step 3: Write the formula for total resistance in series: R_total = R1 + R2 + R3.
Step 4: Substitute the values of the resistors into the formula: R_total = 1Ω + 2Ω + 3Ω.
Step 5: Perform the addition: 1 + 2 + 3 = 6.
Step 6: Conclude that the total resistance in the circuit is 6Ω.

Series Circuit Resistance – In a series circuit, the total resistance is the sum of the individual resistances.