Which haloalkane is most likely to undergo elimination reactions? (2023)
Practice Questions
Q1
Which haloalkane is most likely to undergo elimination reactions? (2023)
1-bromopropane
2-bromobutane
3-bromobutane
Bromobenzene
Questions & Step-by-Step Solutions
Which haloalkane is most likely to undergo elimination reactions? (2023)
Step 1: Understand what haloalkanes are. Haloalkanes are organic compounds that contain carbon, hydrogen, and halogen atoms (like bromine).
Step 2: Know what elimination reactions are. Elimination reactions involve the removal of a small molecule (like HBr) from a larger molecule, resulting in the formation of a double bond.
Step 3: Identify the types of carbon in haloalkanes. Carbon atoms can be classified as primary, secondary, or tertiary based on how many other carbon atoms they are connected to.
Step 4: Recognize that tertiary carbons are more likely to undergo elimination reactions. This is because they are more stable and can better accommodate the formation of a double bond.
Step 5: Look at the example of 3-bromobutane. It has a tertiary carbon (the carbon attached to the bromine is connected to three other carbons).
Step 6: Conclude that 3-bromobutane is more likely to undergo elimination reactions because of its tertiary carbon structure.
