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For the parabola defined by the equation x^2 = 16y, what is the distance from the vertex to the focus?

Practice Questions

1 question
Q1
For the parabola defined by the equation x^2 = 16y, what is the distance from the vertex to the focus?
  1. 2
  2. 4
  3. 8
  4. 16

Questions & Step-by-step Solutions

1 item
Q
Q: For the parabola defined by the equation x^2 = 16y, what is the distance from the vertex to the focus?
Solution: In the equation x^2 = 4py, we have 4p = 16, thus p = 4. The distance from the vertex to the focus is 4.
Steps: 0

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