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The vertex of the parabola given by the equation y = 2x^2 - 4x + 1 is located at
Practice Questions
Q1
The vertex of the parabola given by the equation y = 2x^2 - 4x + 1 is located at which point?
(1, -1)
(2, 0)
(1, 0)
(0, 1)
Questions & Step-by-Step Solutions
The vertex of the parabola given by the equation y = 2x^2 - 4x + 1 is located at which point?
Steps
Concepts
Step 1: Identify the coefficients from the equation y = 2x^2 - 4x + 1. Here, a = 2 and b = -4.
Step 2: Use the formula for the x-coordinate of the vertex, which is x = -b/(2a).
Step 3: Substitute the values of a and b into the formula: x = -(-4)/(2*2).
Step 4: Simplify the expression: x = 4/4 = 1.
Step 5: Now that we have x = 1, substitute this value back into the original equation to find y.
Step 6: Calculate y by plugging x = 1 into the equation: y = 2(1)^2 - 4(1) + 1.
Step 7: Simplify the equation: y = 2(1) - 4 + 1 = 2 - 4 + 1 = -1.
Step 8: The vertex of the parabola is at the point (1, -1).
No concepts available.
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