Question: What is the latent heat of fusion of ice if 80 calories are required to melt 20 grams of ice? (2020)
Options:
40 cal/g
60 cal/g
80 cal/g
100 cal/g
Correct Answer: 80 cal/g
Exam Year: 2020
Solution:
Latent heat of fusion (L_f) = Q / m = 80 cal / 20 g = 4 cal/g.
What is the latent heat of fusion of ice if 80 calories are required to melt 20
Practice Questions
Q1
What is the latent heat of fusion of ice if 80 calories are required to melt 20 grams of ice? (2020)
40 cal/g
60 cal/g
80 cal/g
100 cal/g
Questions & Step-by-Step Solutions
What is the latent heat of fusion of ice if 80 calories are required to melt 20 grams of ice? (2020)
Step 1: Understand the problem. We need to find the latent heat of fusion of ice, which is the amount of heat required to melt ice without changing its temperature.
Step 2: Identify the given values. We know that 80 calories (Q) are required to melt 20 grams (m) of ice.
Step 3: Use the formula for latent heat of fusion: L_f = Q / m.
Step 4: Substitute the values into the formula: L_f = 80 cal / 20 g.
Step 5: Perform the division: 80 divided by 20 equals 4.
Step 6: Write the final answer: The latent heat of fusion of ice is 4 cal/g.
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