If 2000 J of heat is added to a system and 500 J of work is done by the system,
Practice Questions
Q1
If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)
1500 J
2000 J
2500 J
3000 J
Questions & Step-by-Step Solutions
If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)
Step 1: Identify the amount of heat added to the system, which is 2000 J. This is represented as Q.
Step 2: Identify the amount of work done by the system, which is 500 J. This is represented as W.
Step 3: Use the formula from the first law of thermodynamics: ΔU = Q - W.
Step 4: Substitute the values into the formula: ΔU = 2000 J - 500 J.
Step 5: Perform the subtraction: 2000 J - 500 J = 1500 J.
Step 6: Conclude that the change in internal energy of the system is 1500 J.
First Law of Thermodynamics – The principle that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.
