My Learning Cart
?
Categories
Account

If 2000 J of heat is added to a system and 500 J of work is done by the system,

₹0.0
Login to Download
  • 📥 Instant PDF Download
  • ♾ Lifetime Access
  • 🛡 Secure & Original Content

What’s inside this PDF?

Question: If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)

Options:

  1. 1500 J
  2. 2000 J
  3. 2500 J
  4. 3000 J

Correct Answer: 1500 J

Exam Year: 2021

Solution: 

Using the first law of thermodynamics: ΔU = Q - W = 2000 J - 500 J = 1500 J.

If 2000 J of heat is added to a system and 500 J of work is done by the system,

Practice Questions

Q1
If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)
  1. 1500 J
  2. 2000 J
  3. 2500 J
  4. 3000 J

Questions & Step-by-Step Solutions

If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)
  • Step 1: Identify the amount of heat added to the system, which is 2000 J. This is represented as Q.
  • Step 2: Identify the amount of work done by the system, which is 500 J. This is represented as W.
  • Step 3: Use the formula from the first law of thermodynamics: ΔU = Q - W.
  • Step 4: Substitute the values into the formula: ΔU = 2000 J - 500 J.
  • Step 5: Perform the subtraction: 2000 J - 500 J = 1500 J.
  • Step 6: Conclude that the change in internal energy of the system is 1500 J.
  • First Law of Thermodynamics – The principle that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely
Home Practice Performance eBooks