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If 2000 J of heat is added to a system and 500 J of work is done by the system,
If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)
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If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)
1500 J
2000 J
2500 J
3000 J
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Using the first law of thermodynamics: ΔU = Q - W = 2000 J - 500 J = 1500 J.
Questions & Step-by-step Solutions
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Q
Q: If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)
Solution:
Using the first law of thermodynamics: ΔU = Q - W = 2000 J - 500 J = 1500 J.
Steps: 6
Show Steps
Step 1: Identify the amount of heat added to the system, which is 2000 J. This is represented as Q.
Step 2: Identify the amount of work done by the system, which is 500 J. This is represented as W.
Step 3: Use the formula from the first law of thermodynamics: ΔU = Q - W.
Step 4: Substitute the values into the formula: ΔU = 2000 J - 500 J.
Step 5: Perform the subtraction: 2000 J - 500 J = 1500 J.
Step 6: Conclude that the change in internal energy of the system is 1500 J.
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