What is the work done by an ideal gas during an isobaric expansion if it expands

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Question: What is the work done by an ideal gas during an isobaric expansion if it expands from 2 L to 5 L at a pressure of 3 atm? (2022)

Options:

Correct Answer: 15 J

Exam Year: 2022

Solution:

Work done (W) = P * ΔV = 3 atm * (5 L - 2 L) = 3 atm * 3 L = 9 atm·L = 15 J (1 atm·L = 101.325 J)

What is the work done by an ideal gas during an isobaric expansion if it expands from 2 L to 5 L at a pressure of 3 atm? (2022)

What is the work done by an ideal gas during an isobaric expansion if it expands from 2 L to 5 L at a pressure of 3 atm? (2022)

Step 1: Identify the initial volume (V1) and the final volume (V2) of the gas. Here, V1 = 2 L and V2 = 5 L.
Step 2: Calculate the change in volume (ΔV) by subtracting the initial volume from the final volume: ΔV = V2 - V1 = 5 L - 2 L.
Step 3: Calculate ΔV: ΔV = 3 L.
Step 4: Identify the pressure (P) at which the gas is expanding. Here, P = 3 atm.
Step 5: Use the formula for work done (W) during isobaric expansion: W = P * ΔV.
Step 6: Substitute the values into the formula: W = 3 atm * 3 L.
Step 7: Calculate the work done: W = 9 atm·L.
Step 8: Convert the work done from atm·L to Joules using the conversion factor (1 atm·L = 101.325 J): W = 9 atm·L * 101.325 J/atm·L.
Step 9: Calculate the final work done in Joules: W = 9 * 101.325 = 911.925 J.
Step 10: Round the answer if necessary, but here we keep it as 911.925 J.

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