What is the equation of the circle with center at (2, -3) and radius 5?

₹0.0

Question: What is the equation of the circle with center at (2, -3) and radius 5?

Options:

Correct Answer: (x-2)² + (y+3)² = 25

Solution:

Standard form of a circle: (x-h)² + (y-k)² = r². Here, h=2, k=-3, r=5.

What is the equation of the circle with center at (2, -3) and radius 5?

What is the equation of the circle with center at (2, -3) and radius 5?

Step 1: Identify the center of the circle. The center is given as (2, -3). Here, h = 2 and k = -3.
Step 2: Identify the radius of the circle. The radius is given as 5, so r = 5.
Step 3: Write the standard form of the circle's equation, which is (x - h)² + (y - k)² = r².
Step 4: Substitute the values of h, k, and r into the equation. This gives us (x - 2)² + (y + 3)² = 5².
Step 5: Calculate 5², which is 25. So the equation becomes (x - 2)² + (y + 3)² = 25.

No concepts available.