For which value of k does the equation x^2 + kx + 16 = 0 have equal roots? (2019

Practice Questions

Q1
For which value of k does the equation x^2 + kx + 16 = 0 have equal roots? (2019)
  1. -8
  2. -4
  3. 4
  4. 8

Questions & Step-by-Step Solutions

For which value of k does the equation x^2 + kx + 16 = 0 have equal roots? (2019)
  • Step 1: Understand that for a quadratic equation ax^2 + bx + c = 0 to have equal roots, the discriminant must be zero.
  • Step 2: Identify the coefficients from the equation x^2 + kx + 16 = 0. Here, a = 1, b = k, and c = 16.
  • Step 3: Write the formula for the discriminant, which is D = b^2 - 4ac.
  • Step 4: Substitute the values of a, b, and c into the discriminant formula: D = k^2 - 4*1*16.
  • Step 5: Simplify the expression: D = k^2 - 64.
  • Step 6: Set the discriminant equal to zero for equal roots: k^2 - 64 = 0.
  • Step 7: Solve the equation k^2 - 64 = 0 by adding 64 to both sides: k^2 = 64.
  • Step 8: Take the square root of both sides: k = ±8.
  • Step 9: Since the question asks for the value of k, we can choose k = -8.
  • Discriminant – The discriminant of a quadratic equation determines the nature of its roots; for equal roots, it must be zero.
  • Quadratic Equation – A polynomial equation of the form ax^2 + bx + c = 0, where a, b, and c are constants.
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