If a + b = 12 and a^2 + b^2 = 70, what is the value of ab? (2019)

Practice Questions

Q1
If a + b = 12 and a^2 + b^2 = 70, what is the value of ab? (2019)
  1. 20
  2. 22
  3. 24
  4. 25

Questions & Step-by-Step Solutions

If a + b = 12 and a^2 + b^2 = 70, what is the value of ab? (2019)
  • Step 1: Start with the equations given: a + b = 12 and a^2 + b^2 = 70.
  • Step 2: Recall the identity that relates a^2 + b^2 to a + b and ab: a^2 + b^2 = (a + b)^2 - 2ab.
  • Step 3: Substitute the value of a + b into the identity: (a + b)^2 = 12^2 = 144.
  • Step 4: Now rewrite the identity using the values we have: a^2 + b^2 = 144 - 2ab.
  • Step 5: Set the equation equal to the value of a^2 + b^2: 70 = 144 - 2ab.
  • Step 6: Rearrange the equation to solve for ab: 2ab = 144 - 70.
  • Step 7: Calculate 144 - 70, which equals 74: 2ab = 74.
  • Step 8: Divide both sides by 2 to find ab: ab = 74 / 2 = 37.
  • Algebraic Identities – Understanding and applying the identity a^2 + b^2 = (a + b)^2 - 2ab to relate sums and products of variables.
  • System of Equations – Solving for unknowns using given equations involving sums and squares.
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