If x + y = 10 and xy = 21, what is the value of x^2 + y^2? (2021)

Practice Questions

1 question
Q1
If x + y = 10 and xy = 21, what is the value of x^2 + y^2? (2021)
  1. 49
  2. 59
  3. 61
  4. 41

Questions & Step-by-step Solutions

1 item
Q
Q: If x + y = 10 and xy = 21, what is the value of x^2 + y^2? (2021)
Solution: We know that x^2 + y^2 = (x + y)^2 - 2xy. Substituting the values, we get (10)^2 - 2(21) = 100 - 42 = 58.
Steps: 0

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